could you please help me with this problem as soon as possible 01. Assuming that the speci?c heat of salt is 0.22 Kcal/ (kg °C), water is 1 Kcal/ (kg °C), and ice is 0.5 Kcal! (kg °C), calculate the specific heat of the water saltmixtures you made (use mass weighted averages). This means C (mixture) = m1C1 + m202/(m1+ m2) Here is one example: Mass of salt = 50 g Mass of water = 100 9 Plug the numbers into the equation to get C (mixture) = 0.74 Kcall (kg °C)
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https://www.npr.org/sections/ed/2018/04/25/605092520/high-paying-trade-jobs-sit-empty-while-high-school-grads-line-up-for-university Click on the link above. Read the entire link and answer the questions below…
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