How many of these alleles are for the recessive condition | Quick Homework Help
A mutation has occurred in an animal population so that the homozygous recessive condition (ff) results in a fatal disease for the animal. Affected individuals die soon after birth. The homozygous dominant (FF) and the heterozygous (Ff) individuals live normally. A study of the population over one year found that 4% of the newborn individuals died soon after birth. An equal number of males and females died. Using a punnett square and the Hardy-Weinberg Principle, calculate the frequencies of the alleles in the new generation. Then answer the questions that follow.
a.Assume that 100 individuals were born in the animal population. How many of these 100 animals would probably be carriers (het¬erozygous) of the allele for the recessive trait?
b.How many of these 100 animals would not carry the allele for the recessive trait?
c.Assume that the 96 surviving individuals of the new generation become a new breeding population. What is the total combined number of the two alleles in the breeding population?
d.How many of these alleles are for the dominant condition?
e.How many of these alleles are for the recessive condition?
f.What is the frequency of the allele for the dominant condition in the new breeding population?
g.What is the frequency of the allele for the recessive condition in the new breeding population?
h.What happened to the allele frequencies in a single generation?
i.Selection is operating against which allele?
j.If this situation were to continue for several generations, what would be the result?
k.Lethal recessive genes never disappear from a population. Why?
